Thank for your quick reply Pokemon.
R1 = 10 power [(1/10)*(PdB - a(dR-dx)^b - c)]
R2 = 10 power [(1/10)*(PdB - a'(dR^ b') - c')]
where a different from a' (another variable independant from a, not a conjugate)
similarely for b and b', and c and c'.
f(dR) = R1*R2*(S^2) - (2^(2*Clim) - 1)*(1 + S*(R1 + R2)) = 0
Actually, I also think ask what you suggest by represent (R1+R2)=s and R1*R2 = p
than use the equation X^2 - sX + p = 0 to find R1 and R2 and then to find dR.
However, I have only one equation but 2 variables.
Thank you anyways for your effort.
I will try the find the way out today (by using approximation method some where)
and if I can, I will informe you as well.
Best regards
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